Decimal to Binary Converter

Helped me cheat in my electrical electronics test

@madan
I have always had a problem with Binary. I found it easiest to remember the power of 2 up to a certain number (usually 128 is something I start with), and then you can extrapolate up from there. So what I do to do this freehand, I start with a number I know, let's say you remember 64 is the highest 2 bit operator you remember, so I multiply that until I get over the number I have to convert. So 1024 is too large, so 512 is the first binary number that isn't too large, so you set the bit to 1.
1
Next is 256, and the remainder from subtracting 512 from 789 is 277. You set the bit to 1 to indicate 256.
11
Next is 128, but your remainder is 21. That bit is 0.
110
64, bit is 0.
1100
32, your remainder is 21, so the bit is 0.
11000
16, which is less than 21. So the bit is 1. Remainder is now 5.
110001
8 is the next 2 bit, it's greater than 5 so the bit is 0.
1100010
4, remainder 1. Bit is 1
11000101
2, bit is 0
110001010
1, bit is 1
1100010101
It's tedious, but works. I checked against the calculation on the page, and it's accurate. If you need to put it in bytes, it would be 0011 0001 0101. Each byte is 4 bits, zero padded

it is a very good application i wish that i cn download this app

29.135 decimal to binary

Thanks alot
Great effort

Cool helped cheat in ICT

What about converting a number such as 125.625

Great for cheating in ICT thanks a lot. Really good website

THis Website is Very Nice. It Done My Work So Easy.

Really good for cheating in my Computer Science test.

keep up the good work

Nice work!

Amazing, all around thank you so much for this site. It’s wonderful.

Explain the each steps skills e can do well

@madan
I have always had a problem with Binary. I found it easiest to remember the power of 2 up to a certain number (usually 128 is something I start with), and then you can extrapolate up from there. So what I do to do this freehand, I start with a number I know, let's say you remember 64 is the highest 2 bit operator you remember, so I multiply that until I get over the number I have to convert. So 1024 is too large, so 512 is the first binary number that isn't too large, so you set the bit to 1.
1
Next is 256, and the remainder from subtracting 512 from 789 is 277. You set the bit to 1 to indicate 256.
11
Next is 128, but your remainder is 21. That bit is 0.
110
64, bit is 0.
1100
32, your remainder is 21, so the bit is 0.
11000
16, which is less than 21. So the bit is 1. Remainder is now 5.
110001
8 is the next 2 bit, it's greater than 5 so the bit is 0.
1100010
4, remainder 1. Bit is 1
11000101
2, bit is 0
110001010
1, bit is 1
1100010101
It's tedious, but works. I checked against the calculation on the page, and it's accurate. If you need to put it in bytes, it would be 0011 0001 0101. Each byte is 4 bits, zero padded.

any body help me to solve this (789) 10 =( ?) 2

it would be cool if it showed how it got the calculations

It really helped me with my test.

Its Really helped my work

I should just say thanks a lot. it's helped me and the text was useful.
thanks again.